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son4ous [18]
3 years ago
14

what is the equation of a line, in point-slope form, that passes through (5, -3) and has a slope of 2/3? please help me

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

y + 3 = \frac{2}{3} (x - 5)

the equation of a line in point- slope form is

y - b = m ( x - a )

where m is the slope and (a, b) a point on the line

here m =\frac{2}{3} and (a,b) = (5 , - 3 )

y + 3 = \frac{2}{3} (x - 5 ) ← in point-slope form


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mars1129 [50]
This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

  (6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12        Divide both sides by 6.
     x > -12/6
     x > -2.

Combined solution:   x < 4/3  and x > -2

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Graph is a line on the number line between -2 and 4/3.  
 
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8 0
3 years ago
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jolli1 [7]

Answer:

C

Step-by-step explanation:

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therefore y ≥ x² - 3x and y ≤ x + 1

6 0
3 years ago
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kow [346]

Answer:

  1. 150π ft²
  2. 10π ft.

Step-by-step explanation:

Area of the sector :

Area (sector) = \pi r^{2} \times \frac{\theta}{360^{o}}

Finding the area given r = 30 ft. and θ = 60° :

⇒ Area = π × (30)² × 60/360

⇒ Area = π × 900/6

⇒ Area = 150π ft²

===========================================================

Length of the arc :

Length (arc) =2 \pi r} \times \frac{\theta}{360^{o}}

Finding the arc length given r = 30 ft. and θ = 60° :

⇒ Arc Length = 2 × π × 30 × 60/360

⇒ Arc Length = 60/6 × π

⇒ Arc Length = 10π ft.

7 0
2 years ago
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alexdok [17]

Answer:

The answer is 20/80.

Step-by-step explanation:

1/4=5 yards

? =100 yards

100÷5=20

1/4×20

=20/80.

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2 years ago
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Answer:

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