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Sophie [7]
3 years ago
8

In order to determine students’ preferences, Ms. Lewis took a random survey of 60 high school students and found that 42 of them

preferred multiple-choice tests to free-response typed tests. Use the results to predict the approximate number of students out of 180 who prefer multiple-choice tests?
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

126 students

Step-by-step explanation:

42/60 = 126180

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Five more than 3/4 of a number C is 26 find the number
Furkat [3]

Answer:

28

Step-by-step explanation:

let x be the number,

(3/4)x+5=26

(3/4)x=21

x=21*(4/3)

x=28

8 0
3 years ago
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What are -7 like terms?
atroni [7]

Answer:

In algebra, like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers.

5 0
3 years ago
A 20ft ladder leans against a building and it touches the building 18ft above the ground. What is the angle of elevation that th
sammy [17]

Answer:

The angle is [/tex]64.1581^{\circ}[/tex]

Step-by-step explanation:

You can figure this out using the sine function:

\sin(v)=\frac{18 ft}{20 ft} \\= \frac{9}{10}\\ v= \arcsin(\frac{9}{10} )\\= 64.1581^{\circ}

5 0
3 years ago
Please help me with this!!!!!!!!!!!
Lorico [155]

Answer:

just make a mark in the center i think thats where the it should be

Step-by-step explanation:

the question is asking to mark the midpoint of line AB which technically means the area where the line is bisected or in other words cut in two equal parts so just mark where line AB is cut in half

5 0
3 years ago
Which of the following points lies on the circle whose center is at the origin and whose radius is 5?
ad-work [718]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2751733

_______________


Equation of the circumference whose center is at \mathsf{C(0,\,0)} and whose radius is \mathsf{r=5:}

\mathsf{(x-x_C)^2+(y-y_C)^2=r^2}\\\\
\mathsf{(x-0)^2+(y-0)^2=5^2}\\\\
\mathsf{x^2+y^2=25}


We are looking for the point that satisfies the equation above.


<span> •  </span>Testing \mathsf{(-3,\,4):}

\mathsf{(-3)^2+4^2}\\\\&#10;\mathsf{9+16}\\\\&#10;\mathsf{25\qquad\quad\checkmark}


The point \mathsf{(-3,\,4)} lies in the circumference.


<span> •  </span>Testing \mathsf{(1,\,-2):}

\mathsf{1^2+(-2)^2}\\\\ \mathsf{1+4}\\\\ \mathsf{5\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}


The point \mathsf{(1,\,-2)} doesn't lie in the circumference.


<span> •  </span>Testing \mathsf{(\sqrt{5},\,\sqrt{5}):}

\mathsf{(\sqrt{5})^2+(\sqrt{5})^2}\\\\ \mathsf{5+5}\\\\ \mathsf{10\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}


So, the point \mathsf{(\sqrt{5},\,\sqrt{5})} doesn't lie in the circumference either.



Answer:  (<span>–3,  4</span>).


I hope this helps. =)

8 0
4 years ago
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