Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
FVAO=2500[((1+0.013/4)^(4*25)-1)/(0.013/4]
FVAO=294,847.29
The answer is c
Answer:
2x+4
Step-by-step explanation:
Distribute:
=(2)(x)+(2)(−6)+(2)(8)
=2x+−12+16
Combine Like Terms:
=2x+−12+16
=(2x)+(−12+16)
=2x+4
Assuming you'd like to know about how much malinda spent at the circus,
21.10+3.25+9.05 = 33.4
or about 33 dollars.
in the form 
