When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
$274.77
Step-by-step explanation:
213.00 ÷29 =61.769999 then add 213.00 plus 61.76
I actually rounded up maybe I shouldn't of then answer would be $274.76. im not postive this is correct .
Answer:
8244
Step-by-step explanation:
The value of the function is the Y value where the line crosses the given X value.
When X is at -2, the line is on Y = 3
The answer would be y =3
<span>if point A( 2,2) is reflected across the line Y then the new position A' is (-2,2) and the distance AY = distance A'Y
if A is reflected across line R it is now at point B and the distance AR = distance BR
lets say the point A(2,2) was perpendicular to the line R at the point (1, 4) then when reflected the point A now at location B will have coordinates</span><span>when flipped over a line of reflection the lengths are still the same
the point to the line of reflection is the same length as the line of reflection to the reflected position
the distance from the original point to the reflected point is twice the distance from the original point to the line of reflection
cannot see your polygon.
here is an example
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