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Feliz [49]
2 years ago
9

Nomonde earns a total salary of R63 420 p.a . Deductions from her salary amount to R5 785 for the year . Her other expenses are

R130 rent per week , R3 890 transport for the year , R1 200 food, groceries and entertainment per month , R400 phone and internet per month , R7 220 clothes, books , stationery for the year .
Is the amount she earns enough to cover her annual expenses? to answer this question, first sort out the weekly , monthly, and annual expenses listed above. Multiply each weekly expense by 52, and each monthly expense by 12 . Then add their subtotals to the other annual expenses to get her total expense for the year . Then subtract this total from Nomonde's total annual salary


​
Mathematics
1 answer:
WINSTONCH [101]2 years ago
4 0

Answer: R63 420 p.a. earning is enough to cover her annual expenses and get R20 565 extras

Step-by-step explanation:

Let's do a simple calculation,

Her total earning = R63 420 per year

Deduction from salary = R 5 785 per year

Now

1 year has 52 weeks and 12 months approximately

So, convert all expenses in per year by calculating with no. of week and months,

Rent deduction = 52 weeks × R130 = R6760 per year

Transport deduction = R3 890 per year

Food, entertainment = R1 200 × 12 month = R14 400 per year

Phone and internet = R400 × 12 month = R4 800 per year

Stationary and clothers = R7 220 per year

Now lets Subtract all deduction from total salary, we get

Extras = Total salary per year - Total deduction per year

Extras = R63 420 - (R5 785 + R6 760 + R3 890 + R14 400 + R4 800 + R7 220)

Extras = R20 565

So after dudction of all expense she has extra R20565, i.e the amount she earns is enough to cover her annual expenses.

#SPJ9

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Estimate the sum or difference.
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1) \frac{4}{6}+\frac{1}{8}=\frac{19}{24}

2) \frac{2}{6}+\frac{7}{8}=\frac{29}{24}

3) \frac{5}{6}-\frac{3}{8}=\frac{11}{24}

4) \frac{4}{6}+\frac{3}{8}=\frac{25}{24}

5) \frac{7}{8}-\frac{5}{6}=\frac{1}{24}

6) \frac{1}{6}+\frac{7}{8}=\frac{25}{24}

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

1)

\frac{4}{6}+\frac{1}{8}=

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

4\cdot 4 = 16\\1\cdot 3 = 3

The expression then becomes:

\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}

2)

\frac{2}{6}+\frac{7}{8}=

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.  

So the new numerators of the two fractions are:

2\cdot 4 = 8\\7\cdot 3 = 21

And we get:

\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}

3)

\frac{5}{6}-\frac{3}{8}

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

5\cdot 4 = 20\\3\cdot 3 = 9

And so:

\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}

4)

\frac{4}{6}+\frac{3}{8}=

Using the same lowest common denominator, 24, the new numerators are:

4\cdot 4 = 16\\3\cdot 3 = 9

And so we can rewrite the expression as

\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}

5)

\frac{7}{8}-\frac{5}{6}=

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

7\cdot 3 = 21\\5\cdot 4 = 20

So the expression will be rewritten as:

\frac{7}{8}-\frac{5}{6}=\frac{21}{24}-\frac{20}{24}=\frac{21-20}{24}=\frac{1}{24}

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Here the situation is similar to the first 4 exercises: using 24 as lowest common denominator, the numerators become

1\cdot 4 = 4\\7\cdot 3 = 21

So the expression becomes

\frac{1}{6}+\frac{7}{8}=\frac{4}{24}+\frac{21}{24}=\frac{4+21}{24}=\frac{25}{24}

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

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