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belka [17]
3 years ago
11

What are the solutions to the quadratic equation 3(x - 4)2 = 75?

Mathematics
1 answer:
Sever21 [200]3 years ago
5 0

Answer:

(9,-1)

(I assume you meant to put 3(x-4)^2=75.)

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‼️would appreciate help
horrorfan [7]
<span>Median of Triangle is </span>a line segment from a vertex to the midpoint of the opposite side.

If segment AE is a median of ΔABC, then
<em><u>segments BE and EC are congruent</u></em><em>
</em>
7 0
3 years ago
How many phone numbers are possible in the (770) area code if: For the form ABC-XXXX, A is restricted to numbers 2-9. B, C, and
weqwewe [10]

Answer:

c.7,999,999

Step-by-step explanation:

The phone number is of the form ABC - XXXX

A can be any number from 2 - 9. This means number of possible values for A are 8.

The rest of the places B,C and X can be any digit from 0 - 9. This means there are 10 possible values for each of these.

Since, value to A can be assigned in 8 ways, and to the rest of the 6 positions in 10 ways, according to the fundamental rule of counting, the total number of possible phone numbers that can be formed will be equal to the product of all the individual ways:

Total possible phone numbers = 8 x 10 x 10 x 10 x 10 x 10 x 10

Since, 1 of the given number: 867-5309 is not used, the total possible phone numbers will be:

Total possible phone numbers = 8 \times 10^{6} - 1 = 7999999

Hence, option C: 7,999,999 give the correct answer.

6 0
3 years ago
Solve the inequality. 4(p – 4) &gt; 12 A. p 3 C. p &gt; 16 D. p &gt; 7 it would be nice if you can show me how you did step by s
anzhelika [568]

Answer:

D

Step-by-step explanation:

Given

4(p - 4) > 12 ( divide both sides by 4 )

p - 4 > 3 ( add 4 to both sides )

p > 7 → D

7 0
3 years ago
A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the
Dafna1 [17]
Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
5 0
3 years ago
Anyone know this geometry question? 10 min left! Will give brainiest
Rasek [7]
Angle 3 and angle 6 are corresponding angles, which means they are equal. In order for the lines to remain parallel, angle 3 and angle 6 would need to remain equal. If something is done to angle 6, then it would have to be done to angle 3 as well in order to keep the angles equal. So, if angle 6 is doubled, angle 3 would also have to be doubled. 

The answer is B. m< 3 would need to double.

Hope this helps =)
5 0
3 years ago
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