9.
By the Segment Addition Postulate, SAP, we have
XY + YZ = XZ
so
YZ = XZ - XY = 5 cm - 2 cm = 3 cm
10.
M is the midpoint of XZ=5 cm so
XM = 5 cm / 2 = 2.5 cm
11.
XY + YM = XM
YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm
12.
The midpoint is just the average of the coordinate A(-3,2), B(5,-4)
Answer: M is (1,-1)
You'll have to plot it yourself.
13.
For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.
Answer: AB=10
M is the midpoint of AB so
Answer: AM=MB=5
14.
B is the midpoint of AC. We have A(-3,2), B(5,-4)
B = (A+C)/2
2B = A + C
C = 2B - A
C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)
Check the midpoint of AC:
(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good
Answer: C is (13, -10)
Again I'll leave the plotting to you.
Solutions
In Matrix we use initially based on systems of linear equations.The matrix method is similar to the method of Elimination as but is a lot cleaner than the elimination method.Solving systems of equations by Matrix Method involves expressing the system of equations in form of a matrix and then reducing that matrix into what is known as Row Echelon Form.<span>
Calculations
</span>⇒ <span>Rewrite the linear equations above as a matrix
</span>
![\left[\begin{array}{ccc}3&5&42\\6&5&54\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%265%2642%5C%5C6%265%2654%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
⇒ Apply to Row₂ : Row₂ - 2 <span>Row₁
</span>
![\left[\begin{array}{ccc}3&5&42\\0&-5&-30\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%265%2642%5C%5C0%26-5%26-30%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
⇒ <span>Simplify rows
</span>
![\left[\begin{array}{ccc}3&5&42\\0&1&6\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%265%2642%5C%5C0%261%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
Note: The matrix is now in echelon form.
<span>The steps below are for back substitution.
</span>
⇒ Apply to Row₁<span> : Row</span>₁<span> - </span>5 Row₂
![\left[\begin{array}{ccc}3&0&12\\0&1&6\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%2612%5C%5C0%261%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
⇒ <span>Simplify rows
</span>
![\left[\begin{array}{ccc}1&0&4\\0&1&6\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%264%5C%5C0%261%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
⇒ <span>Therefore,
</span>
<span>
</span>
Answer:
-89/40 or simplified it is -2 9/40
Answer: 7 x 80 i think
Step-by-step explanation:\
nothing
Answer:
61.712
Step-by-step explanation:
Multiply .8x.04
Multiply .8x.0
Multiply .8x2
Multiply .8x2
Than add a zero under the answer of .8x.04
Multiply 2x.04
Multiply 2x.0
Multiply 2x2
Multiply 2x 2
