Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
Hello!
This can be written as
(x) + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 270
Add all the values
5x + 1 + 2 + 3 + 4 = 270
Combine like terms
5x + 10 = 270
Subtract 10 from both sides
5x = 260
Divide both sides by 5
x = 52
So the numbers are 52, 53, 54, 55, 56,
Hope this helps!
Answer:
18 + (4*5) = 38
because 4 * 5 is 20 then 20 + 18 is 38, and that's your answer.
have a nice day! :)
3(2)-18=-12
6-18 = -12
-12 = -12
2 is greater then -5.
2 is a positive number unlike -5 it is a negative which is less then 2.
