Find numbers that multiply to 28 and add them to see if they add to 8 28= 1 and 28=29 not 8 2 and 14=16 not 8 4 and 7=11 not 8 that's it' no 2 numbers we must use quadratic formula
x+y=8 xy=28
x+y=8 subtract x fromb oths ides y=8-x subsitute x(8-x)=28 distribute 8x-x^2=28 add x^2 to both sides 8x=28+x^2 subtract 8x x^2-8x+28=0
if you have ax^2+bx+c=0 then x= so if we have 1x^2-8+28=0 then a=1 b=-8 c=28
x= x= x= x= x= there are no real numbers that satisfy this