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eduard
3 years ago
14

Point E has a negative x-coordinate, and its y-coordinate is not 0. Where could point E be located on the coordinate plane? Choo

se all answers that apply: (Choice A) Quadrant I (Choice B) Quadrant II (Choice C) Quadrant III (Choice D) Quadrant IV (Choice E) x-axis (Choice F) y-axis
Mathematics
2 answers:
Nostrana [21]3 years ago
3 0

Answer:

B, C, and F.

Step-by-step explanation:

since there is a negative x-coordinate, it has to be on the left side of the coordinate plane. There are only 2 Quadrants on that side, Quadrant II, and quadrant III. It also said that the y-coordinate is not 0, so It cannot be on the x-axis becuase that would mean that the y-coordinate is 0, but it said nothing about the x-coordinate not being 0.

ikadub [295]3 years ago
3 0

Answer:

x-axis thas the answer ghs

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WARRIOR [948]
\bf 16sin^5(x)+2sin(x)=12sin^3(x)
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-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
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\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
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~~~~~~~~~~~~\textit{quadratic formula}
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\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
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sin(x)= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}
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\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}

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\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
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\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
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\approx~0.252680~radians\\
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3 0
3 years ago
What function is vertically stretched by a factor of 3 and translated 4 units right from the parent function
Neporo4naja [7]
<span>The <u>correct answer</u> is:

B) 3log</span>₅<span>(x-4).

Explanation<span>:

To stretch a function by a factor of 3, we multiply the function by 3. This eliminates A and D.

To translate a function 4 units right, we add -4 to the variable before anything else is applied to it; this eliminates C.

In choice B, the log function is multiplied by 3, which gives us our vertical stretch; and the x is subtracted by 4 before anything else is applied to it, so it is translated 4 units right.</span></span>
4 0
3 years ago
Read 2 more answers
Two sisters, Lily and Suri, have been saving money for college for the past several years. At the end of the first year, each si
andriy [413]

Answer:

1st year:

Lily:20

Suri:20

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3rd year

L:60*3=180

S:100+80=180

4th year

L 180*3=540

S 180+80=260

It will take Lily 4 years to hve more money saved than Suri

Step-by-step explanation:

8 0
3 years ago
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Stels [109]

Answer:

y=0.5x

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3 0
3 years ago
The vertices of figure KLMN are
Molodets [167]

Answer:

N'(9, -1)

Step-by-step explanation:

N(-5, -1)

Point N has x-coordinate -5. It is 5 units to the left of the the y-axis, and another 2 units away from the line x = 2. That makes point N 7 units to the left of the line x = 2. 7 units to the right of line x = 2, the x-coordinate is 2 + 7 = 9.

Answer: N'(9, -1)

8 0
3 years ago
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