Point E has a negative x-coordinate, and its y-coordinate is not 0. Where could point E be located on the coordinate plane? Choo
2 answers:
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Answer:
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -9 ,-8)
point B( x₂ , y₂ )≡ (-15 ,-16)
To Find:
Slope = ?
Solution:
Slope of Line Segment AB is given as
Substituting the values we get
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is
Assume x <span>> 0
</span>√(2x⁵/18)
= √(2/18) * √(x⁵)
= √(1/9) * √(x⁴ · x)
= 1/3 * √x⁴ * √x
= 1/3 * x² * √x
= 1/3 * x²√x
=
</span>√(2x⁵/18)
= √(2/18) * √(x⁵)
= √(1/9) * √(x⁴ · x)
= 1/3 * √x⁴ * √x
= 1/3 * x² * √x
= 1/3 * x²√x
=