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sergij07 [2.7K]
3 years ago
6

if a molecule of carbon dioxide is involved in a chemical reaction, how is it represented in the chemical equation for the react

ion?
Chemistry
1 answer:
DIA [1.3K]3 years ago
4 0
Im mot sure but you could ask my mum
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Which type of ion most likely will be formed by group 16 elements of the periodic table?
elena55 [62]

Either covalent or ionic... they are nonmetals meaning that the are a component in both types of compounds
4 0
3 years ago
Which description of salt is a chemical property?
andre [41]

Answer: No combustion

Explanation:

8 0
3 years ago
wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.
Papessa [141]

<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  A+2B\xrightarrow[]{K_1} 2C

<u>Equation 2:</u>  2C\xrightarrow[]{K_2} D

The net equation follows:

D\xrightarrow[]{K} A+2B

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K=K_1\times \frac{1}{K_2}

We are given:

K_1=2.57

K_2=0.226

Putting values in above equation, we get:

K=2.57\times \frac{1}{0.226}=11.37

Hence, the value of equilibrium constant for the net reaction is 11.37

6 0
3 years ago
Which of these is not a process of chemical weathering?
Alekssandra [29.7K]
A cracked sidewalk definitely isn’t a process of chemical weathering.
6 0
3 years ago
How much liquid is needed to prepare 629.1mL of a solution that has a new concentration of 11.2M if the stock solution is 26.1M
slega [8]

Answer:

270. mL

General Formulas and Concepts:

<u>Acid-Base Titrations</u>

Dilution: M₁V₁ = M₂V₂

  • M₁ is stock molarity
  • V₁ is stock volume
  • M₂ is new molarity
  • V₂ is new volume

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] V₂ = 629.1 mL

[Given] M₂ = 11.2 M

[Given] M₁ = 26.1 M

[Solve] V₁

<u>Step 2: Find Stock Volume</u>

  1. Substitute in variables [Dilution]:                                                                     (26.1 M)V₁ = (11.2 M)(629.1 mL)
  2. Multiply:                                                                                                             (26.1 M)V₁ = 7045.92 M · mL
  3. Isolate V₁ [Cancel out units]:                                                                            V₁ = 269.959 mL

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs as our lowest.</em>

269.959 mL ≈ 270. mL

5 0
3 years ago
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