We are given a scale that for every 1 in on the plan, the actual length will 6.5 ft.
The maximum distance across the pond on the plan is 9.75 in. So that means we will need to take 6.5 ft 9.75 times. So our answer is
6.5*9.75=63.375 ft. That's the answer.
We can visualize this a different way
1 in = 6.5 ft
9.75 in = x ft
And from here it's a little more clear to see what needs to be done.
Hope this helped!
Answer:
Area = 2025 miles²
Perimeter = 180 miles
Step-by-step explanation:
Given the following :
Scale of drawing = 1 inch : 5 miles
Length of side of the scale drawing = 9 inches
To find The actual perimeter and area of the square, we need ;
Actual length of the drawing :
1 inch = 5 miles
9 inches = (5 × 9) miles = 45 miles
Hence,
Area of a square = a²
Where a = side length
Actual side length = 45 miles
Actual area of square = 45² = 2025 miles²
Actual Perimeter of square :
Perimeter of a square = 4a
a = side length
Actual perimeter = 4(45) = 180 miles
Answer:
true!
Step-by-step explanation:
plug in 1.1
3 + 51(1.1) = 59.1
3 + 56.1 = 59.1
59.1=59.1
Answer:
Approximate length of the diagonal fencing needed is 45.25 cm.
Step-by-step explanation:
Here, each side of the square shaped land = 32 ft
Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.
<u>In the triangle:</u>
Base side of the triangle = 32 cm
Perpendicular length of the triangle = 32 cm
Let us assume the hypotenuse of the triangle = k cm
⇒The length of the diagonal in the square = k cm
by <u>PYTHAGORAS THEOREM</u> in a right angled triangle:
⇒
or, k = 45.25 cm
Hence,the approximate length of the diagonal fencing needed to fence the square land is 45.25 cm.
