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Maksim231197 [3]
3 years ago
12

a local businesses bought a square ploy of land. the sides of the lot measure 32 feet on each side. he decides to split the lot

into two equal sized right triangles by putting a fence down the diagonal. approximately how many feet of fencing I'll he need?​
Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

Approximate length of the diagonal fencing needed   is  45.25 cm.

Step-by-step explanation:

Here, each side of the square shaped land = 32 ft

Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.

<u>In the triangle:</u>

Base side of the triangle  = 32 cm

Perpendicular length of the triangle = 32 cm

Let us assume the hypotenuse of the triangle = k cm

⇒The length of the diagonal in the square = k cm

by <u>PYTHAGORAS THEOREM</u> in a right angled triangle:

(Base)^{2} +  (Perpendicular)^{2}  =  (Hypotenuse)^{2}

⇒(32)^2 + (32)^2  =k^2\\or, k^2  = 1024 + 1024 =  2048\\\implies k = \sqrt{2048}  = 45.25

or, k = 45.25 cm

Hence,the approximate length of the diagonal fencing needed  to fence the square land is  45.25 cm.

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