All categories

2 years ago

HELP!! PLEASE!!!!!

Mathematics

2 answers:

aleksandr82 [10.1K]2 years ago

5 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

n=5, -5

8090 [49]2 years ago

4 0

Answer:

$n=\frac{3i\sqrt{22}-2}{-8}$

Step-by-step explanation:

$(2-8n)^2=-198$

$\sqrt{(2-8n)^2} =\sqrt{-198}$

$2-8n=i\sqrt{198}$

$2-8n=3i\sqrt{22}$

$-8n=3i\sqrt{22} -2$

$n=\frac{3i\sqrt{22}-2}{-8}$

I hope this helps!

You might be interested in

-n+(-3)+3n+5<br><br> Combing like terms :

Karolina [17]

Answer: 2n + 2 should be your answer

3 0

2 years ago

Quadrilateral A’B’C’D’ is a dilation of ABCD about point F.

Kamila [148]

The answer to the equation is 2.5

7 0

2 years ago

I will upvote and give brainliest answer

zloy xaker [14]

Answer:

x=17

Step-by-step explanation

i just did the exact same question on a test and got it right .

6 0

3 years ago

The circumference of a circle is 28.888 centimeters. What is the circle's radius?

DanielleElmas [232]

Answer:

4.6

Step-by-step explanation:

28.888 / 3.14 = 9.2

9.2 / 2 = 4.6

5 0

2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago