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4 years ago

Electricity is added to recharge a battery. What is added to ADP to form ATP?

Biology

2 answers:

White raven [17]4 years ago

7 0

Answer:

The correct answer is B) A third phosphate group.

Explanation:

ATP is Adenosine Tri<em>phosphate</em> and ADP is Adenosine Di<em>phosphate</em>.

ADP gets converted into ATP in presence of inorganic phosphate and energy, irrespective of whether the energy is obtained from sunlight or from certain exothermic reactions. ATP is converted into ADP, releasing energy and inorganic phosphate.

Cheers!

White raven [17]4 years ago

6 0

Electricity is added to recharge a battery. A third phosphate group is added to ADP to form ATP.

ATP or Adenosine triphosphate contains adenine, ribose and 3 phosphate groups.

ADP is converted to ATP by the following reaction:

ADP+Pi+energy⇄ATP

The analogy between battery and ATP can be explained as ATP is higher energy form and ADP is lower energy form like charged and uncharged form of the battery. When the terminal or third phosphate is removed from the ATP it becomes ADP and releases energy like a battery. The additional phosphate group when added to ADP forms the ATP molecule like the energy spent by the batteries are recharged by putting in additional energy. Here the additional energy is provided by the third phosphate group.

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3 years ago

Read 2 more answers

Which theory is currently accepted as explaining the Moon's creation?

aliya0001 [1]

Explanation:

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3 years ago

In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t

Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² + 2pq+ q² = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = $\sqrt{0.35}$ = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

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3 years ago

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3 years ago

What stage are these cells in?

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