5 then 11 then .2 in as decimal
Pls mark branliest!
Answer: 18/7
Step-by-step explanation: random.
<h3>
Answer: k = 0 or k = 3</h3>
Explanation:
If you have repeated x values, then you wont have a function. For example, the points (1,5) and (1,6) mean we don't have a function since the input x = 1 leads to multiple outputs y = 5 and y = 6 simultaneously. For a function to be possible, we must have any input lead to exactly one output only.
What we do is set the x coordinates (k^2 and 3k) equal to each other and solve for k
k^2 = 3k
k^2-3k = 0
k(k-3) = 0 .... factoring
k = 0 or k-3 = 0 .... zero product property
k = 0 or k = 3
If k = 0, then (k^2,5) becomes (0,5). Also, (3k,6) becomes (0,6). The two points (0,5) and (0,6) mean the graph fails the vertical line test.
Similarly, if k = 3, then (k^2,5) becomes (9,5) and (3k,6) = (9,6). Another vertical line test failure happens here to show we don't have a function.
Answer:
48
Step-by-step explanation:
. .
=12 = ,
12+12=24 =24 = ,
24+24= 48
48
