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andreyandreev [35.5K]
2 years ago
11

Rationalise 1/√7-√3PLEASE GIVE ANSWER IT'S URGENT ​

Mathematics
1 answer:
IgorLugansk [536]2 years ago
5 0

\dfrac 1{\sqrt  7- \sqrt 3}\\\\\\=\dfrac{\sqrt 7 + \sqrt 3}{\left ( \sqrt 7 -\sqrt 3\right) \left( \sqrt 7 + \sqrt 3\right)}\\\\\\=\dfrac{\sqrt 7 + \sqrt 3}{\left(\sqrt  7 \right)^2 - \left(\sqrt 3 \right)^2}\\ \\\\=\dfrac{\sqrt 7 + \sqrt 3}{7-3}\\\\\\=\dfrac  14\left(\sqrt 7 + \sqrt 3\right)

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Which of the following is a trinomial with a constant term O A. -x + y10 O B. x3 + 11x2 + x O C. x + 4y+ 7 O D.​
Kamila [148]

Answer:

<h2><em><u>C. x + 4y+ 7</u></em></h2>

Step-by-step explanation:

As,

In it there are three different terms x, 4y and 7 hence a trinomial, then there is a constant term 7.

5 0
2 years ago
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What is the common ratio of the geometric sequence 16, 24, 36, 54, ...? 1 8
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3 years ago
The tThe term 10x3y2 is a term in which binomial expansion?
MAXImum [283]

Answer:

(x + y)^5.

Step-by-step explanation:

The (r+1)th term of (x + y)^n = nCr x^n-r y^r

Compare this with 10x^3 y^2  we get

nCr = 10 , n-r = 3 and r = 2 giving n = 3+2 = 5

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So the answer is (x + y)^5.

6 0
3 years ago
-3×+7y=5<br> -8×+14y=-10<br> By elimination
dimaraw [331]
-3x+7y=5 (x2) -> -6x+14y=10

-6x+14y=10
-8x+14y=-10
——————— -
2x=20
x=20/20
x=1

Susbstitute x=1,

-8x+14y=-10
-8(1)+14y=-10
-8+14y=-10
14y=-10+8
14y=-2
y=-2/14
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I hope it helps
5 0
3 years ago
You bought your car for $12500 and it is depreciating at 13% per year. How long until it is only worth half of what you paid for
il63 [147K]

Answer:

5 years

Step-by-step explanation:

We are given;

  • Initial value of the car = $12,500
  • Rate of Depreciation = 13% per year
  • New value (after depreciation) = $6,250 (half the initial value)

We are required to determine the time taken for the value of the car to depreciate to half the original value.

  • We need to know the depreciation formula;
  • New value = Initial value ( 1 - r/100)^n

Therefore;

$6,250 = $12,500(1 - r/100)^n

0.5 = (1 - 13/100)^n

0.5 = 0.87^n

Introducing log on both sides;

log 0.5 = n log 0.87

Therefore;

n = log 0.5 ÷ log 0.87

  = 4.977

  = 5 years

Therefore, it takes 5 years for the value of the car to depreciate to half the initial value.

5 0
3 years ago
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