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andreyandreev [35.5K]
2 years ago
11

Rationalise 1/√7-√3PLEASE GIVE ANSWER IT'S URGENT ​

Mathematics
1 answer:
IgorLugansk [536]2 years ago
5 0

\dfrac 1{\sqrt  7- \sqrt 3}\\\\\\=\dfrac{\sqrt 7 + \sqrt 3}{\left ( \sqrt 7 -\sqrt 3\right) \left( \sqrt 7 + \sqrt 3\right)}\\\\\\=\dfrac{\sqrt 7 + \sqrt 3}{\left(\sqrt  7 \right)^2 - \left(\sqrt 3 \right)^2}\\ \\\\=\dfrac{\sqrt 7 + \sqrt 3}{7-3}\\\\\\=\dfrac  14\left(\sqrt 7 + \sqrt 3\right)

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CAN ANYONE DO IT PLZ.
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Step-by-step explanation:

The law of sines is a property of all triangles that relates the sides and angles of a triangle. This property states the following:

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Where side (A) is the side opposite angle (<a), side (B) is the side opposite angle (<b), and side (C) is the property opposite angle (<c).

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One can shorten the equation so it only holds the parts that will play a role in solving this equation,

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