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ollegr [7]
3 years ago
8

Please help I have no idea how to do this. I’m about to cry literally I can’t with math anymore helppppp

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

I think you would times the exponents by each other and keep them in the parenthesis.

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What is the value of the six in 106,534
aleksley [76]
6,000 because its in the thousandth and so since its a six in the thousandths its 6,000 remember the comma
8 0
3 years ago
A number cube has a volume of 27 mm3. What is the length of one edge of the cube
disa [49]
If the volume of a cube is 27 it means that one edge is equal to the cube root of 27
3*3*3=27
Edge=3

I hope it was helpful
8 0
3 years ago
there are 298 students in the third grade. if 227 students take the bus to school, about how many students do not take the bus?
Blizzard [7]

71 because 298-227=71 which is the remaining students

4 0
3 years ago
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Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

∴ x = 30m

3 0
3 years ago
Asap pleaseeeee Name a point that lies only on the y-axis?
maxonik [38]

Answer:

(0,1)

Step-by-step explanation:

hope this helps !

could u check out my recent question I asked no one has helped me and I'm stuck and I'm also kinda slow . pleaseee

5 0
3 years ago
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