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strojnjashka [21]
2 years ago
15

Determine the measure of each indicated angle. Show all necessary steps!

Mathematics
1 answer:
Mariana [72]2 years ago
7 0

The measure of the unknown angle are; a) x = 89 degrees, b) p = 92 degrees.

<h3>What is the sum of all the angles of a regular polygon?</h3>

For a regular polygon of any number of sides, the sum of its exterior angle is 360°.

We already know that a 4-sided polygon's angles add up to 360 degrees.

So to find the value of x:

69 + 118 + 84 + x = 360

x = 360 - (69 + 118 + 84)

x = 89 degrees

b)

For a 4-sided polygon, we also know that the outside angles add up to 360 degrees.

So to find the value of p:

100 + 62 + 106 + p = 360

p = 360 - (100 + 62 + 106)

p = 92 degrees

Learn more about interior angles of a regular polygon here:

brainly.com/question/14173422

#SPJ1

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frutty [35]

9514 1404 393

Answer:

  x = 58

Step-by-step explanation:

The external angle is half the difference of the intercepted arcs.

  (160° -x°)/2 = 51°

  160 -102 = x = 58

5 0
3 years ago
PLEASE PLEASE HELP!!!!
Gennadij [26K]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
A school chorus has 90 sixth-grade students and 75 seventh-grade students. The music director wants to make groups of performers
Vera_Pavlovna [14]

Answer:

a) 15 is the largest number of groups that can be made.

b) There would 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

Number of sixth-grade students = 90

Number of seventh-grade students = 75

a) What is the largest number of groups that could be formed?

Since the music director wants to make groups with the same combination of sixth and seventh grade students in each group,

The greatest common factor (GCF) of the number of sixth and seventh grade students would give us the required combination.

Factor of 90 = 2*45 = 2*3*15 = 2*3*3*5

Factor of 75 = 3*25 = 3*5*5

The greatest common factors are 3 and 5

GCF = 3*5 = 15

Therefore, 15 is the largest number of groups that can be made.

b. If that many groups are formed, how many students of each grade level would be in each group?

Sixth grade = 90/15 = 6

Seventh grade = 75/15 = 5

Therefore, there would 6 sixth grade students and 5 seventh grade students in each group.

7 0
3 years ago
What could the answer be?
VashaNatasha [74]

Answer:

it 66

Step-by-step explanation:

8 0
3 years ago
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