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Ymorist [56]
2 years ago
6

Which expression has a term with a coefficient greater than 1?

Mathematics
1 answer:
Cloud [144]2 years ago
3 0

Answer:

B

Step-by-step explanation:

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Please help!!! Answer needed fast<3
zhannawk [14.2K]

Answer:

-5 + 6 = 1

Step-by-step explanation:

The model number may be used to simplify -5 + 6 = 1

3 0
2 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
If his truck pulls forward with a force of 2,750 newtons and the weight of the trailer pulls backward with a force of 2,790 newt
Orlov [11]
The answer is A. the force will always pull back a lot deals with gravitational pull
3 0
3 years ago
Read 2 more answers
Please help! I attached the file below
LiRa [457]

Answer:

1/5

Step-by-step explanation:

5 0
2 years ago
Match each equation to its factorized version and solution.
bagirrra123 [75]

Answer:

24x -{6x}^{2}  = 0 \: matches \: with \: 6x(4 - x) \: and \: the \: solution \: x = 0 \ \: or \:  \: x = 4

2 {x}^{2}  + 6x = 0 \: matches \: with \: 2x(x + 3) = 0 \: and \: the \: solution \: x = 0 \: or \: x =  - 3

4x -  {x}^{2}  = 0 \: matches \: with \: x(4 - x) = 0 \: and \: the \: solution \: x = 0 \: or \: x = 4

14x -  {7x}^{2}  = 0 \: matches \: with \: 7x(2 - x) = 0 \: and \: the \: solution \: x = 0 \: or \: x = 2

5 0
3 years ago
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