Answer:
<em>$7,196.42 </em>
Step-by-step explanation:
Using the compound interest formula to fins the amount after 10years;
A = P(1+r)^n
Principal P = $400,000
Rate r = 8% = 0.08
Time t = 10 years
Substitute
A = 400,000(1+0.08)^10
A = 400,000(1.08)^10
A = 400,000(2.1589)
A = 863,569.99
A ≈ 863,570
Hence the amount after 10 years is $863,570
Monthly deposit = $863,570/120 (10 years is equivalent to 120months)
Monthly deposit = 7,196.42
<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>
I think you meant "y = 4 arccot (x)."
This is equivalent to:
y
---- = arccot x
4
and so cot (y/4) = x
I cant help you there m8 the I'm not able to see the problem I'm sorry.
Compounded depreciation formula:
A = P(1 - r)ⁿ , where P = original price, r= rate of depreciation, n = number of years and A = actual value (after depreciation):
A= $8000(1 - 11%)⁵ = 8000(0.89)⁵ = 4,467.24 ≈$4,467
It might be d but i’m not sure