5. 80, 16/.2=80
6. 679, 750-70.75
7. 7.82, 10-2.18
8. 36.07, 29.62+1.29+ 1.29+ 1.29+ 1.29+ 1.29
There are
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have

The last expression has a more compact form in terms of the so-called multinomial coefficient,

<span>y = 50x/(x+33)
x≠-33
xy + 33y = 50x
33y = x(50-y)
33y/(50-y)= x
or y≠50
=> yϵ R - {50} </span>
For Question Number one
(2+10)²+4=148
Question Number two:
(6+5)×(8-6)=22