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andreyandreev [35.5K]
3 years ago
11

Which fraction is equivalent to 38%? 3/8 9/25 19/50 3 4\5

Mathematics
2 answers:
KonstantinChe [14]3 years ago
5 0
In order to find a fraction, We know that a percentage is out of a 100. This means we can now place our fraction as:

38/100

In order to find the actual fraction, we will want to simplify. Lets find our least common factor and work down from there. Since we know that 2 can go into both of them, lets reduce by 2.

This means our fraction will now look like: 

19/50

Since 19 is a prime number and cannot be divided by anything but 1 and itself, we know that this is our simplified form. 

This means:

19/50 is the fraction equivalent to 38%. 
Alchen [17]3 years ago
4 0

Answer:

19/50

Step-by-step explanation:

you just have to trust me on this

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Find the slope of the line that passes through (-11, 75) and (27, -9).
Marrrta [24]

Answer:

\frac{y__2-y__1}{x__2-x__1}

y = -9 + 75 = 66

x = 27-(-11) = 27 + 11 = 38

slope = 66/28

5 0
2 years ago
P(a) = 2a -3; find p(a) = 15
Andrei [34K]
Since both is equal to p(a), you can set them as equal to each other:

15 = 2a - 3
18 = 2a
9 = a
8 0
3 years ago
What’s 3/4 x 22/7 x 2
Zolol [24]

Answer:

4\frac{5}{7}

Step-by-step explanation:

we just multiply numerator by numerator and denominator by denominator

3/4x22/7

66/28x2/1

132/28

4 20/28

4 5/7

Hopes this helps,please mark brainliest

3 0
1 year ago
Read 2 more answers
A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
One over x+10 plus 20 over x squared - 100 =1
bagirrra123 [75]

Answer:

x=11

Step-by-step explanation:

3 0
2 years ago
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