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nexus9112 [7]
2 years ago
9

Find the value of u to the nearest tenth of a centimeter

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
7 0

Answer:

u = 3.8 cm

Step-by-step explanation:

Since these triangles are similar, we can use a proportion to solve:

\frac{8}{6}= \frac{5}{u}

Cross multiply:

8u = 30

Divide both sides by 8:

3.75 cm

Round to nearest tenth:

3.8 cm

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

     ★ Also please leave the rating you think I deserve (It helps other users learn as well as helps me improve my answers)

- Heather

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.02 level tha
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Answer:

The p-value of the test statistic is 0.2019.

Step-by-step explanation:

Test if there is evidence at the 0.02 level that the medicine relieves pain in more than 384 seconds.

At the null hypothesis, we test if it relieves pain in at most 384 seconds, that is:

H_0: \mu \leq 384

At the alternative hypothesis, we test if it relieves pain in more than 384 seconds, that is:

H_1: \mu > 384

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

384 is tested at the null hypothesis:

This means that \mu = 384

For a sample of 41 patients, the mean time in which the medicine relieved pain was 387 seconds. Assume the population standard deviation is 23.

This means that n = 41, X = 387, \sigma = 23

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{387 - 384}{\frac{23}{\sqrt{41}}}

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P-value of the test:

The p-value of the test is the probability of finding a sample mean above 387, which is 1 subtracted by the p-value of z = 0.835.

Looking at the z-table, z = 0.835 has a p-value of 0.7981.

1 - 0.7981 = 0.2019

The p-value of the test statistic is 0.2019.

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2 years ago
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