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4 years ago

Which process would release energy from gold, fission or fusion? from carbon?

1 answer:

4 0

The process that would release energy from gold is fission; while from carbon it would be fusion. Nuclear fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and nuclear fusion is the process where two light nuclei combine together releasing vats amounts of energy.

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Create an example in which a mutation entered the gene pool and due to predator pressure. Becomes predominate. For example, thin

Genrish500 [490]

Answer:

The population of light colour Peppered moths decreases and dark Peppered moths increases.

Explanation:

During the industrial revolution, the population of light colour Peppered moths decreases and dark Peppered moths increases because due to industrial revolution, air pollution increases which spreads a black dust on the trees and as a result the light colour Peppered moths can easily be seen in the dark by its predator and feed on them while dark colour Peppered moths can't be seen in the dark so the predator is unable to feed and as a result the population of dark colour Peppered moths increases.

7 0

3 years ago

As the earth revolves around the sun, it’s tilted 23.5° angle in relation to the sun.

alina1380 [7]

Answer: true..? idrk tbh srry!

Explanation:

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3 years ago

Occurs when the population is well below the carrying capacity.

Alexeev081 [22]

Answer:

Explanation:

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3 years ago

Which is the best description of a tropical climate zone? O A. High altitude O B. Warm all year long O C. Thick sheets of ice O

VMariaS [17]

Answer: Hewo, there! your answer is Below

B. Warm all year long

Explanation:

here are normally only two seasons in tropical climates, a wet season and a dry season. The annual temperature range in tropical climates is normally very small. Sunlight is intense.

Hope this helps!

Have a great day!!

3 0

3 years ago

Michelle was curious about her mother's blood type. Michelle knew that her own blood type was o,

babymother [125]

Blood type is determined by the I gene. IAIA and IAi determines A blood type. IBIB and IBi determines B blood type. ii determines 0 blood type. Michelle's mother must at least carry one recessive allele i.

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The blood type is determined by a gene, which is triallelic.

IA dominant over i. The person presents A type of antigens.

IB dominant over i. The person presents B type of antigens.

IA and IB are codominant. The person presents both types of antigens, A and B.

i is the recessive allele. The person does not present any antigen.

⇒ H0m0zyg0us dominant individuals IAIA, or heter0zyg0us Individuals IAi, will express the A blood type.

⇒ H0m0zyg0us dominant individuals IBIB, or heter0zyg0us Individuals IBi, will express the B blood type.

⇒ Individuals with h0m0zyg0us recessive genotype, ii will express the 0 blood type.

⇒ Individuals carrying IA and IB alleles will express the AB blood type.

To solve the problem, we will use this information.

We know that

Michelle is blood type 0

Father is blood type A

Brother and sister are blood type A

Mother??

⇒ If Michelle is blood type 0, then her genotype is ii. She must have received one recessive allele from her father and one from her mother.

⇒ This suggests that Michelle's father, who is blood type A, is heter0zyg0us IAi. He must have at least one dominant allele IA that determines his phenotype, and one i allele.

⇒ Michelle's brother and sisters are also type A. They might be either h0m0zyg0us dominant IAIA or heter0zyg0us IAi.

⇒ Michelle's mother should have at least one recessive allele i. She could be either IAi or IBi, or ii. There are three possible option for her genotype.

Let us make the Punnet squares to understand it better. We know the genotype of the father, but there are three options for the mother.

Option 1

Cross) father x mother

Parentals) IAi x IAi

Gametes) IA i IA i

Punnett square) IA i

IA IAIA IAi

i IAi ii

F1) 25% of the progeny is expected to be h0m0zyg0us dominant IAIA

50% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be h0m0zyg0us recessive ii

75% of the progeny is expected to be blood type A ⇒ IAIA and IAi ⇒ Sisters and brother

25% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Option 2

Cross) father x mother

Parentals) IAi x IBi

Gametes) IA i IB i

Punnett square) IA i

IB IBIA IBi

i IAi ii

F1) 25% of the progeny is expected to be IAIB

25% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be heter0zygus IBi

25% of the progeny is expected to be h0m0zyg0us recessive ii

25% of the progeny is expected to be blood type AB ⇒ IAIB

25% of the progeny is expected to be blood type A ⇒ IAi ⇒ Sisters and brother

25% of the progeny is expected to be blood type B ⇒ IBi

25% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Option 3

Cross) father x mother

Parentals) IAi x ii

Gametes) IA i i i

Punnett square) IA i

i IAi ii

F1) 50% of the progeny is expected to be heter0zygus IAi

25% of the progeny is expected to be h0m0zyg0us recessive ii

50% of the progeny is expected to be blood type A ⇒ IAi ⇒ Sisters and brother

50% of the progeny is expected to be blood tye 0 ⇒ ii ⇒ Michelle

Despite the fact we can not determine for sure the mother's genotype, we know that she carries at least one recessive allele, which is why Michelle's blood type is 0.

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8 0

3 years ago