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Likurg_2 [28]
3 years ago
12

An Urn contains two white marbles and one black marble. A marble is drawn from the Urn without replacement and put aside without

my seeing it. Then a second marble is drawn, and it is white.
What is the probability that the unknown removed marble is white, and what is the probability that it is black?
Mathematics
1 answer:
algol [13]3 years ago
4 0

Answer:

Step-by-step explanation:

No. Of white marble n(W) = 2

No. Of black marble n(B) = 1

Total no. Of marble N = 2 + 1 = 3

Prob(1st is white) = n(W)/N = 2/3

Prob(1st is black) = n(B)/N = 1/3

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Answer:

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C and D are mutually exclusive events. Find P(C or D).<br> P(C)= 3/7= P(D)= 4/7<br> P(C or D)
IgorLugansk [536]

Answer:

P(C\ or\ D) = 1

Step-by-step explanation:

Given

P(C) = \frac{3}{7}

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Required

P(C\ or\ D)

Since the events are mutually exclusive, then:

P(C\ or\ D) = P(C) + P(D)

So, we have:

P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}

Take LCM

P(C\ or\ D) = \frac{3+4}{7}

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P(C\ or\ D) = 1

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