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zubka84 [21]
3 years ago
5

Rs=st then points is called the midpoint of rt

Mathematics
1 answer:
icang [17]3 years ago
3 0
So what is the question
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Will mark brainlist and rate 5/5
erastova [34]
Sir you don’t even have a question
5 0
3 years ago
Simplify.
otez555 [7]
The answer to the question is C.
6 0
3 years ago
How can i find values if h(-4) h(x)=1/2x-1???
anzhelika [568]

plug in -4 in for x. then solve.

h(-4)=1/2(-4)-1

h(-4)= -3

6 0
3 years ago
When I count as a principal of $1000 and earns 4% simple interest per year and other account as a principal $1000 and earns 4% i
OLga [1]

Answer: the account that earned compound interest has the greater balance at the end of four years.

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the amount invested.

P represents the principal or amount invested.

R represents interest rate

T represents the duration of the investment in years.

From the information given,

P = 1000

R = 4%

T = 4 years

I = (1000 × 4 × 4)/100 = 160

Total amount earned is

1000 + 160 = $1160

The formula for determining compound interest is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 1000

r = 4% = 4/100 = 0.04

n = 1 because it was compounded once in a year.

t = 4 years

Therefore,.

A = 1000(1+0.04/1)^1 × 4

A = 1000(1.04)^4

A = $1170

3 0
3 years ago
In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi
Nataliya [291]

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

3 0
3 years ago
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