Answer:
Q1
cos 59° = x/16
x = 16 cos 59°
x = 8.24
Q2
BC is given 23 mi
Maybe AB is needed
AB = √34² + 23² = 41 (rounded)
Q3
BC² = AB² - AC²
BC = √(37² - 12²) = 35
Q4
Let the angle is x
cos x = 19/20
x = arccos (19/20)
x = 18.2° (rounded)
Q5
See attached
Added point D and segments AD and DC to help with calculation
BC² = BD² + DC² = (AB + AD)² + DC²
Find the length of added red segments
AD = AC cos 65° = 14 cos 65° = 5.9
DC = AC sin 65° = 14 sin 65° = 12.7
Now we can find the value of BC
BC² = (19 + 5.9)² + 12.7²
BC = √781.3
BC = 28.0 yd
All calculations are rounded
Answer:
x² + 6x - 27 = 0
x² + 9x - 3x - 27 = 0
x ( x + 9 ) - 3 ( x + 9 ) = 0
( x + 9 ) ( x - 3 ) = 0
Thus ,
x = -9 or x = 3
I hope it helps you
#Indian : )
Answer:
Step-by-step explanation:
One off fee is 120 Dirhams and weekly charge is 200 Dirhams.
<u>The equation for this relation is:</u>
- y = 200x + 120, where x- the number of weeks
42/60, x/320. 320/60=5.33333, 42*5.33333=224. So, about 224 students would ride the bus.
Answer:
For the first one: they increase in by 14, so the three could be 73,87,101
Second: Sequential, increasing by 20, next could be 110, 130, 150
Third: Increase by 27, next three could be 122,149,176
