Yuck, trig. I'm doing college trig at this very moment.
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
Well, solve for x.
Combine like terms by performing the opposite operation of subtracting 4x on both sides of the equation
The 4x's will cross out on the right
4x - 4x = 0x = 0
On the left:
2x - 4x = -2x
Now the equation looks like:
-2x + 3 = 2
Continue to combine like terms by subtracting 3 on both sides of the equation
On the left:
3 - 3 = 0
On the right:
2 - 3 = -1
Equation:
-2x = -1
Isolate x by performing the opposite operation of dividing -2 on both sides of the equation
On the left:
-2x ÷ -2 = 1
On the right:
-1 ÷ -2 = 1/2
x= 1/2
So, there is only one solution: 1/2
What are you supposed to be doing
Answer:
d
Step-by-step explanation:
M = 5 and x = 4
3(5) - 2(4)
15 - 8 = 7
I hope this helps!
