Three numbers are in ration 3: 4: 8. The sum of the two larger numbers exceeds twice the smallest by 48. Find the numbers.
2 answers:
Answer:
24, 32, 64
Step-by-step explanation:
12x=6x+48
-6x -6x
6x=48
x=8
8(3)=24
8(4)=32
8(8)=64
Answer:
24, 32, 64
Step-by-step explanation:
1st=3x
2nd=4x
3rd=8x
2(3x)+48=4x+8x
6x+48=12x
48=6x
x=8
SO:
1st =24
2nd= 32
3rd= 64
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