The formula is
A=p (1+r/k)^kt
A amount of the withdrawal?
P present value 4000
R interest rate 0.06
K compounded monthly 12
T time 2 years
A=4,000×(1+0.06÷12)^(12×2)
A=4,508.64
So it's c
Answer:
<
Step-by-step explanation:
Inequality symbols:
< less than
> greater than
= equal to
≤ less than or equal to
≥ greater than or equal to
In this case, it is known that -4 is less than 5, or:
-4 < 5.
~
I believe 3b/6a which could reduce to b/3a.
Answer:
Problem 2): 
which agrees with answer C listed.
Problem 3) : D = (-3, 6] and R = [-5, 7]
which agrees with answer D listed
Step-by-step explanation:
Problem 2)
The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

Problem 3)
notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:
Domain = (-3, 6]
For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:
Range = [-5, 7]
since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.