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3 years ago

What is the area of this figure?

Mathematics

2 answers:

Makovka662 [10]3 years ago

8 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To solve, you must split the figure into 2 parts --> a rectangle and a trapezoid. The separating 'line' will be where the figure indents and starts to jut out. That separating 'line' will be 9 cm long.

<h3>Area of the rectangle:</h3>

A = bh

A = 9(15)

A = 135

The area of the rectangle is 135 cm².

<h3>Area of the trapezoid:</h3>

A = $\frac{a + b}{2}h$

A = $\frac{9+18}{2}12$

A = $\frac{27}{2}12$

A = $\frac{13.5}{1}12$

A = $13.5(12)$

A = $162$

The area of the trapezoid is 162 cm².

<h3>Area of the figure:</h3>

To find the area of the figure, you must add the area of the rectangle and the area of the trapezoid together.

A = 135 cm² + 162 cm²

A = 297 cm²

<h2>So your answer is --> C) 297 cm²</h2>

I hope this helps!

- sincerelynini

SashulF [63]3 years ago

6 0

Answer:

297 cm2

Step-by-step explanation:

rectangle area = length * width

15 * 9 = 135

trapezium area = (base + base) / 2 * height

(9 + 18) / 2 * 12 = 162

135 + 162 = 297

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damaskus [11]

Answer:

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]$

Step-by-step explanation:

To add matrices, we add the corresponding components.

The given matrices is

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]$

We add the corresponding components to get;

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]$

We simplify to get:

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]$

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3 years ago

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Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take o

Anastaziya [24]

Answer:

the cyclists rode at 35 mph

Step-by-step explanation:

Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then

distance= speed*time

since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :

time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train

thus denoting v as the speed of the cyclists :

7/8*L / v = L / 40 mph

v = 7/8 * 40 mph = 35 mph

v= 35 mph

thus the cyclists rode at 35 mph

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liubo4ka [24]

Answer:

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Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

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So ,

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