Question

What is the area of this figure?

Answer 1

PLEASE MARK BRAINLIEST!

Answer:

To solve, you must split the figure into 2 parts --> a rectangle and a trapezoid. The separating 'line' will be where the figure indents and starts to jut out. That separating 'line' will be 9 cm long.

Area of the rectangle:

A = bh

A = 9(15)

A = 135

The area of the rectangle is 135 cm².

Area of the trapezoid:

A = $\frac{a + b}{2}h$

A = $\frac{9+18}{2}12$

A = $\frac{27}{2}12$

A = $\frac{13.5}{1}12$

A = $13.5(12)$

A = $162$

The area of the trapezoid is 162 cm².

Area of the figure:

To find the area of the figure, you must add the area of the rectangle and the area of the trapezoid together.

A = 135 cm² + 162 cm²

A = 297 cm²

So your answer is --> C) 297 cm²

I hope this helps!

- sincerelynini

Answer 2

Answer:

297 cm2

Step-by-step explanation:

• rectangle area = length * width

15 * 9 = 135

• trapezium area = (base + base) / 2 * height

(9 + 18) / 2 * 12 = 162

135 + 162 = 297