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Nesterboy [21]
3 years ago
9

A 75% increase followed by a 33 1/2% decrease​

Mathematics
1 answer:
o-na [289]3 years ago
8 0

After 75% increase followed by a 33 1/2% decrease the net increased is 16.375%.

<u>Solution:</u>

Need to determine net percentage increase or decrease when a value is increased by 75% and then decreased by 33 \frac{1}{2} \% that is 33.5%.

Let’s assume initial value be represented by variable x.

75 \% \text { decrease means } x+75 \% \text { of } x=x+\frac{75}{100} x=x+0.75 x=1.75 x

Now there is decrease of 33.5%

\begin{array}{l}{33.5 \% \text { decrease means } 1.75 x-33.5 \% \text { of } 1.75 x=1.75 x-\frac{33.5}{100} \times 1.75 x} \\\\ {=1.75 x-(0.335 \times 1.75) x=1.75 x-0.58625 x} \\\\ {=1.16375 x}\end{array}

\text { So increase in percentage }=\frac{\text { final value-initial value}}{\text { intial value }}

=\frac{1.16375 x-x}{x} \times 100=16.375 \%

Hence after 75% increase followed by a 33 \frac{1}{2} \% decrease the net increased is 16.375%.

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Answer:

a) P=0.2503

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Step-by-step explanation:

We have this information:

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P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508

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