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3 years ago

20 POINTS

1 answer:

6 0

Answer: 2 inches, 3 inches, or 3.125 and 2.083

Explanations:
The simplest way is to take 20% of the 2.5 inches and go that much above & below 2.5 inches.

2.5 x 20% = 2.5 x 0.20 = 0.5

So 2.5 - 0.5 = 2 inches was predicted
And 2.5 + 0.5 = 3 inches was predicted.

The more complicated way is to see number + 20% of that number = 2.5, and what number - 20% = 2.5.

Which solution sounds more like what you’re doing in class right now?

If it’s the more complicated way:

0.8x = 2.5 (80% of the predicted rain value equals 2.5)
x = 3.125 inches was predicted

1.2x = 2.5 (120% of the predicted rain value equals 2.5)
x = 2.083 inches was predicted

Sorry, this is probably confusing. Let me know what questions you have.

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An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 2 unit

Gala2k [10]

Answer:

475 transistors, 25 resistors and 50 computer chips can be produced.

Step-by-step explanation:

Let us consider, p = Number of transistors.

q = Number of resistors.

r = Number of computer chips.

The following three linear equations according to question,

$3\times p + 3\times q + 2\times r = 1600\\2\times p + 1\times q + 1\times r = 1025\\1\times p + 2\times q + 2\times r = 625$

The matrix form of any system, Ax = B

Where, A = Coefficient matrix

B = Constant vector

x = Variable vector

$A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right], x = \left[\begin{array}{ccc}p\\q\\r\end{array}\right], B = \left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]$

The inverse matrix, $A^{-1}$ can be found by using the following formula,

$A^{-1} = \frac{1}{det A}\times (C_{A}) ^{T}$

Where, det A = Determinant of matrix A.

$C_{A}$ = Matrix of cofactors of A

Now, applying this formula to find $A^{-1}$ ;

$det A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right] = 3\times(2-2)-3\times(4-1)+2\times(4-1) = -3$

Here, $det A\neq 0$ , thus the matrix is invertible.

$C_{A} = \left[\begin{array}{ccc}(2-2)&-(4-1)&(4-1)\\-(6-4)&(6-2)&-(6-3)\\(3-2)&-(3-4)&(3-6)\end{array}\right] = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] \\(C_{A}) ^{T} = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] ^{T} = \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]$

$A^{-1} = \frac{1}{-3}\times\left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right] \\ So, x= \frac{1}{-3} \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]\times\left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]= \frac{1}{-3} \left[\begin{array}{ccc}-1425\\-75\\-150\end{array}\right] = \left[\begin{array}{ccc}475\\25\\50\end{array}\right]$

So, p = 475, q = 25, r = 50.

7 0

3 years ago

Substitute w = 1 and w = 3 to determine if the two expressions are equivalent

Effectus [21]

Answer:

Expressions are not equivalent

Step-by-step explanation:

Given expressions are:

$4(3w+4)\ and\ 16w+12$

Putting w=1 in both expressions

$4(3w+4)\\=4[3(1)+4]\\=4(3+4)\\=4(7)\\=28\\\\16w+12\\=16(1)+12\\=16+12\\=28$

Both expression have value 28 on w=1

Putting w=3 in both expressions

$4(3w+4)\\=4[3(3)+4]\\=4(9+4)\\=4(13)\\=52\\\\16w+12\\=16(3)+12\\=48+12\\=60$

Both expression have different values at w=3

Hence, in order for the expressions to be equivalent they both should produce same value on w=3 too.

So, it can be concluded that both expressions are not equivalent ..

6 0

3 years ago

(–6)² – (–7)²<br><br> I need a step by step process.

Sati [7]

Is the = -13. Is the response

8 0

3 years ago

M(5.9) is the midpoint ofRS. The coordinates of Sare (6,8). What are the coordinates of R?

e-lub [12.9K]

Coordinates of R (4,10)

•————•————•
(?,?) (5,9) (6,8)

You have to see how the x & y changed from point M to S and do the same thing for point R to M

M S
(5,9) >>>> (6,8) (x+1, y-1)

R M
(4, 10) >>>> (5,9) (x+1, y-1)

4 0

3 years ago

An apple farmer is deciding how to use each day's harvest. She can use the harvest to produce apple cider or apple juice for the

Andreas93 [3]

Answer:For this item, we let x and y be the number of bushels of apple that will be used to produce apple cider and apple juice, respectively. The situation above is best represented by the following equations,

x + y = 18

20x + 15y = 330

The values of x and y from the equations above are 12 and 6, respectively. Therefore, 12 bushels will be used to make apple cider and 6 bushels will be used to make apple juice.

Step-by-step explanation:

3 0

3 years ago

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