3 years ago

H=K+log(A/C) isolate a... make a the subject

1 answer:

6 0

$H=K+\log\left(\dfrac{A}{C}\right)\\\\
\log\left(\dfrac{A}{C}\right)=H-K\\\\
\dfrac{A}{C}=10^{H-K}\\\\
\boxed{A=C\cdot10^{H-K}}$

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