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ycow [4]
3 years ago
12

There are 8 large bags of pretzels for a party. Arun uses bowls which hold 2/3 of a bag. How many bowls are needed?????

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

12 bowls are needed

Step-by-step explanation:

# of bowls * 2/3 = 8

# of bowls = 8/(2/3) = 8*3/2

# of bowls = 12

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A fair dice is rolled. Work out the probability of getting a factor of 12.
Pavlova-9 [17]

Answer:

P (factors of 12) = 5/6

Step-by-step explanation:

The possibilities are 1,2,3,4,5,6

Factors of 12 are 1,2,3,4,6,12

So out of the possibilities rolled

1,2,3,4,6 are factors of 12  (5 of the 6)

P (factors of 12) = 5/6

8 0
4 years ago
Read 2 more answers
13.) Springfield Elementary is putting on a school play
Oduvanchick [21]

45 adult tickets and 80 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 6

Cost of 1 children ticket = $ 3.50

<em><u>They sold a total of 125 tickets</u></em>

Therefore,

a + c = 125

c = 125 - a --------- eqn 1

<em><u>They made a total of $550. Therefore, frame a equation as:</u></em>

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = 550

a \times 6 + c \times 3.50 = 550\\

6a + 3.50c = 550 ----------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

6a + 3.50(125 - a) = 550

6a + 437.5 - 3.50a = 550

2.5a = 112.5

<h3>a = 45</h3>

<em><u>Substitute a = 45 in eqn 1</u></em>

c = 125 - 45

<h3>c = 80</h3>

Thus 45 adult tickets and 80 children tickets were sold

3 0
3 years ago
Find the matrices of ​
aniked [119]

\huge{\sf \left[{x-2y\atop 6x-2z}\:\:\:{4y-3\atop 2y-z}\right]=\left[{-3\atop 4}\:\:\:{5\atop 3}\right]}

Creating equations

\\ \sf\longmapsto x-2y=-3\dots(1)

\\ \sf\longmapsto 4y-3=5\dots(2)

\\ \sf\longmapsto 6x-2z=4\dots(3)

\\ \sf\longmapsto 2y-z=3\dots(3)

  • From eq(2)

\\ \sf\longmapsto 4y-3=5

\\ \sf\longmapsto 4y=5+3

\\ \sf\longmapsto 4y=8

\\ \sf\longmapsto y=\dfrac{8}{4}

\\ \bf\longmapsto y=2

  • Put the value in eq(1)

\\ \sf\longmapsto x-2y=-3

\\ \sf\longmapsto x=-3+2y

\\ \sf\longmapsto x=-3+2(2)

\\ \sf\longmapsto x=-3+4

\\ \bf\longmapsto x=1

  • Put the value in eq(4)

\\ \sf\longmapsto 2y-z=3

\\ \sf\longmapsto z=2y-3

\\ \sf\longmapsto z=2(2)-3

\\ \sf\longmapsto z=4-3

\\ \bf\longmapsto z=1

8 0
3 years ago
Translate the following sentence into an equation. Then solve the equation
sweet-ann [11.9K]
The correct option is C.
The difference of a number and 7 is 21 implies that 
n - 7 = 21
To solve for n,
n - 7 = 21
n = 21 + 7 = 28
Therefore, n = 28.
5 0
3 years ago
whole milk is 4% butterfat how much skim milk with 0% butterfat should be added to 32 ounces of whole milk to obtain a mixture t
vivado [14]

Answer:

whole milk 4 ---------------- 32 ounces

skim milk 0 ---------------- x ounces

Mixture 2.5 ---------------- 32 + x ounces

 

4*32+0x =2.5(32 +x)

128+0x= 80+2.5 x

0 x + -2.5 x = 80 - -128

-2.5 x = -48

/ -2.5

x = 19.2

19.2 ounces of 0 % fat skim milk

4 0
3 years ago
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