Answer:
200 × 20 = 4000
speed of the dog is 4000 m/s
Answer:
A) 1000 + 50m
B) 50 could be a monthly bonus of some sort.
C) 1000 is probably monthly salary or another bonus.
Answer:
Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges
Step-by-step explanation:
Cost of one pound of Apple = $2x
Cost of one pound of Grapes = $(6x-5)
Cost of one pound of Oranges = $(x+2)
A shopper purchases one pound each of apples, grapes, and oranges and spends $10.50.
It can be written as: ![2x+6x-5+x+2=10.50](https://tex.z-dn.net/?f=2x%2B6x-5%2Bx%2B2%3D10.50)
We need to find how much the shopper spend on each fruit.
First we need to find value of x by solving equation
![2x+6x-5+x+2=10.50](https://tex.z-dn.net/?f=2x%2B6x-5%2Bx%2B2%3D10.50)
Solving:
![2x+6x+x+2-5=10.50\\9x-3=10.50\\9x=10.50+3\\9x=13.5\\x=\frac{13.5}{9}\\x=1.5](https://tex.z-dn.net/?f=2x%2B6x%2Bx%2B2-5%3D10.50%5C%5C9x-3%3D10.50%5C%5C9x%3D10.50%2B3%5C%5C9x%3D13.5%5C%5Cx%3D%5Cfrac%7B13.5%7D%7B9%7D%5C%5Cx%3D1.5)
The value of x is: x=1.5
Now finding cost of one pound each fruit by putting x=1.5
Cost of one pound of Apple = $2x = 2(1.5) = $3
Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4
Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5
So,
Cost of one pound of Apple = $3
Cost of one pound of Grapes = $4
Cost of one pound of Oranges = $3.5
So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges
Lets say W=Wesley, M=Max, and J=Jared.
So your equations are M=2J, 2M=W, and M+J+W=21days(3 weeks)
So substituting M and W into M+J+W=21 gives you 2J+J+2M=21, substitute M again, to get 2J+J+4J=21 so you get 7J=21 so J= 3 days. Using J=3, substitute in to find M, using M=2J, so M=2(3) so M=6 and using that, substitute into 2M=W, so 2(6)=W so W=12. And 12+6+3=21 to check.