. Find the general term of the sequence 1, 1000, 10 000 000, 1 000 000 000 000 000,...
1 answer:
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48. The surface area of a cylinder is given by
... A = 2πr² + 2πrh = 2πr(r+h)
For r = 13 mi and h = 7 mi, this becomes
... A = 2π(13 mi)(13 mi + 7 mi) = 520π mi²
The surface area of the cylinder is 520π mi² ≈ 1634 mi².
49. The surface area of a rectangular prism is
... A = 2(LW + H(L+W))
For L = 20 m, W = 10 m, H = 7 m, this becomes
... A = 2((20 m)(10 m) + (7 m)(20 m + 10 m)) = 2(200 m² + 210 m²) = 820 m²
The surface area of the prism is 820 m².
50. The formula is the same as for problem 48.
For r = 10 m and h = 13 m, this becomes
... A = 2π(10 m)(10 m + 13 m) = 460π m² ≈ 1445 m²
The surface area of the cylinder is 460π m² ≈ 1445 m².
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When calculations are repetitive, it is convenient to let a calculator or spreadsheet do them.
Answer:
Step-by-step explanation:
Let
x----> the length of the rectangular garden
y---> the width of the rectangular garden
we know that
The perimeter of the rectangle is equal to
we have
so
simplify
------> equation A
Remember that the area of rectangle is equal to
----> equation B
substitute equation A in equation B
----> this is a vertical parabola open downward
The vertex is a maximum
The y-coordinate of the vertex is the maximum area
The x-coordinate of the vertex is the length side of the rectangle that maximize the area
using a graphing tool
The vertex is the point
see the attached figure
so
Find the value of y
The garden is a square
the area is equal to
----> is equal to the y-coordinate of the vertex is correct
Answer:
Volume of the sphere up to two decimal places= cubic yards
Surface area of the sphere up to two decimal places square yards
Step-by-step explanation:
Given:
The radius of the sphere= 1 yard
Volume of a Sphere:
:
cubic yards
Volume of the sphere up to two decimal places= cubic yards
Surface area of the sphere=
Surface area of the sphere up to two decimal places square yards