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anastassius [24]
3 years ago
13

The cylinder shown has a lateral surface area of about 60 square inches. Which answer is closest to the height of the cylinder?

Use 3.14 to approximate pi.
2.12 inches

3.18 inches

6.36 inches

20 inches
Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Answer: 3.18

Step-by-step explanation:

Virty [35]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

Assuming the cylinder has a radius of the cylinder is 3 inches, then r=3

Given that the lateral surface area of the cylinder is 60, then we can use the formula:

L.S.A = 2\pi \: rh

We substitute the values to get;

60 = 2 \times 3.14 \times 3h

We solve for h to get:

h =  \frac{60}{2 \times 3.14 \times 3}  =  \frac{10}{3.14}  = 3.1847

In this case the correct answer is 3.18 inches.

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worty [1.4K]
Pythagorean Theorum since that is what you are trying to prove.
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4 years ago
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Help please this is due soon! I need you to show the work as well <3 pic below
Dafna1 [17]

Answer:

perimeter: 4x+2 area: x^2+x

Step-by-step explanation:

for perimeter, you add x+x+x+x+1+1, which is 4x+2

for area, you multiply x*x+1, which would be x^2+x

7 0
3 years ago
Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How man
nasty-shy [4]
To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy. 

Max was on vacation twice as long as Jared. We can interpret this as  M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, <span>M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
</span><span>M + J + W = 21 [From the old list]
</span>J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one. 
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
<span>(7/2)M = 21 
</span>
Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
(\frac{2}{7})* (\frac{7}{2}m)= (\frac{2}{7})*(21)
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
<span>J = (1/2)M 
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days 
</span>
Wesley was on vacation twice as long as Max so...  W = 2M 
W= 2*6
W = 12
Wesley was on vacation for 12 days. 

Let's double check our answer:
M + J + W = 21 days<span>6 + 3 + 12 = 21   
The numbers work out so the math is correct. Hope this helps and makes sense!</span>
6 0
4 years ago
A rectangular parking lot has an area of 682 square yards. The lot is 22 yards wide. What is the length of the parking lot?
tatuchka [14]
The answer is 31 yards.
4 0
3 years ago
Read 2 more answers
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
4 years ago
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