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enot [183]
3 years ago
5

Tyler has ten coins. Each coin weighs two hundred thirty-one thousands of an ounce. Decide if each expression is equivalent to t

he weight of twn coins and why. Two and thirty-one hundredths

Mathematics
2 answers:
viktelen [127]3 years ago
7 0

Answer: \dfrac{231}{1000}=0.231

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

two and thirty one thousandths are the required expressions.

Step-by-step explanation:

Since we have given that

Number of coins = 10

Weight of each coin = Two hundred thirty one thousands of an ounce.

So, Weight of ten coins would be

\dfrac{231}{1000}\\\\=0.231

Or it can written as

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

or it can be written as

two and thirty one thousandths.

Hence \dfrac{231}{1000}=0.231

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

two and thirty one thousandths are the required expressions.

White raven [17]3 years ago
6 0
The answers that you have circled are correct
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