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enot [183]
3 years ago
5

Tyler has ten coins. Each coin weighs two hundred thirty-one thousands of an ounce. Decide if each expression is equivalent to t

he weight of twn coins and why. Two and thirty-one hundredths

Mathematics
2 answers:
viktelen [127]3 years ago
7 0

Answer: \dfrac{231}{1000}=0.231

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

two and thirty one thousandths are the required expressions.

Step-by-step explanation:

Since we have given that

Number of coins = 10

Weight of each coin = Two hundred thirty one thousands of an ounce.

So, Weight of ten coins would be

\dfrac{231}{1000}\\\\=0.231

Or it can written as

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

or it can be written as

two and thirty one thousandths.

Hence \dfrac{231}{1000}=0.231

\dfrac{2}{10}+\dfrac{3}{100}+\dfrac{1}{1000}

two and thirty one thousandths are the required expressions.

White raven [17]3 years ago
6 0
The answers that you have circled are correct
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The distribution of the test statistic for analysis of variance is the F-distribution. true or false
lubasha [3.4K]

Answer:

True. See explanation below

Step-by-step explanation:

Previous concepts

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Answer:

1x + 4y = 4 ⇒ 6x + 24y = 24

6x -  8y = 0 ⇒ 6x -   8y = 0  

                              32y = 24

                               32     32

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Step-by-step explanation:

up there :D

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