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kolezko [41]
3 years ago
13

Based on the graph, which of the following statements is true? A. B. C. D.

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

The answer you're looking for is D. The total price depends on the number of boxes.

As the number of boxes (x) changes, the price (y) also increases.

Marat540 [252]3 years ago
7 0

we know that

y-axis is total price ($)

x-axis is number of boxes

and we know that

y is dependent variable

x is independent variable

so, y is dependent on x

so, total price ($) is dependent on number of boxes

so, option-D........Answer

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Which relation is a function
olya-2409 [2.1K]

Answer:

The relation that is a function is{ (-1,5), (-2,6), (-3,7) }. A function will not have any repeating x-values, they all have to be different.

\

3 0
2 years ago
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A rectangular box is created by cutting out squares of equal sides
stiks02 [169]
Well, the box will have 7in long 4 in wide and 2 in high
5 0
3 years ago
To divide 572/4 Stanley estimated to place the first digit of the quotient. In which place is the first digit of the quotient?
umka2103 [35]

Answer:

1

Step-by-step explanation:

I'm not quite sure but I think it is the 1st place digit. Because if you set it up as long division the 4 can divide into the 5. Thus, making this the the first place of the digit of the quotient. Hope this helps

7 0
3 years ago
Help me please I need help
cluponka [151]

Answer:

A=5, B=3y

Step-by-step explanation:

Please see attached picture for full solution

3 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
Sunny_sXe [5.5K]

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2} - x }{x(x - 3)(x + 3)}

Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2}  - x}{x( {x}^{2}  - 9)}

Collect like terms

\frac{ {x}^{2}  + 7x + 15 - 5}{x( {x}^{2}  - 9)}

Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

6 0
3 years ago
Read 2 more answers
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