The vertex where the two triangles touch forms a pair of vertical angles, so that the angles on opposites sides of the vertex are congruent. You're shown that two legs of both triangles are congruent. All this tells you that the two triangles are isosceles, and furthermore that they are similar because of the congruence of their "base" angles.
This means
Answer:
Step 1 : Equation at the end of step 1 : (2x - 1) • (x + 7) = 0 Step 2 : Theory - Roots of a product : 2.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately
Step-by-step explanation:
You could solve it ( without a graph) in 2 easy ways :
1 use the equation that you have written in pencil and solve for y
y=3=-x+4
y=-x +1
Or you could use the point slop form after you find the y intercept y=mx+b
-3=4(-1)+b
b= 1
So the answer would be y= -x +1
Hope this help of it does feel free to give the brainliest
Answer:
284cm^2
Step-by-step explanation:
first, we split up the shape into seperate sections that we can easily find the areas of.
i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.
we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.
there are 2 of these, so 32 x 2 = 64cm^2.
now, i chose to seperarte the pentagon into a rectangle and a triangle,
and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.
the area of the rectangle is 150cm^2.
now, for the triangle.
the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.
8 + 7 = 15.
22 - 15 = 7.
now we know that the height of the triangle is 7 cm.
from earlier, we also know the base, which is 10cm.
7 x 10 = 70cm^2.
now we add all these together:
70 + 150 + 64 = 284cm^2
