Answer:
2.75 seconds.
Step-by-step explanation:
We have been given that a ball is dropped from the ground. T represents the time in seconds.
To find the time when the ball was in air, we will equate height of ball with 0 and solve for t.

Upon dividing both sides by 4, we will get:







Since our given function is a downward opening parabola, so ball will be in air between both t-intercepts.
Since the ball touches the ground at 2.75 seconds, therefore, the ball would be in air for approximately 2.75 seconds.
<em>First, you would multiply 2 x 16. </em>
2 x 16 = 32
<em>Using that number, subtract by 8. </em>
32 - 8 = 24
<em>Multiply 3 x 16. </em>
3 x 16 = 48
<em>Subtract the two numbers from step 2 and 3. </em>
48 - 24 = 24
Answer:
![\sum_{n=1}^{25}(3n-2)=925]](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B25%7D%283n-2%29%3D925%5D)
Step-by-step explanation:
The given series is 
The first term of this series is



The second term is



The common difference is

The sum of the first n-terms is given by;
![S_n=\frac{n}{2}[2a_1+d(n-1)]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a_1%2Bd%28n-1%29%5D)
The sum of the first 25 terms of the series is
![S_{25}=\frac{25}{2}[2(1)+3(25-1)]](https://tex.z-dn.net/?f=S_%7B25%7D%3D%5Cfrac%7B25%7D%7B2%7D%5B2%281%29%2B3%2825-1%29%5D)
![S_{25}=\frac{25}{2}[2+3(24)]](https://tex.z-dn.net/?f=S_%7B25%7D%3D%5Cfrac%7B25%7D%7B2%7D%5B2%2B3%2824%29%5D)
![S_{25}=\frac{25}{2}(74)]](https://tex.z-dn.net/?f=S_%7B25%7D%3D%5Cfrac%7B25%7D%7B2%7D%2874%29%5D)
![S_{25}=925]](https://tex.z-dn.net/?f=S_%7B25%7D%3D925%5D)
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Answer: 
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Given: 
Find: 
Solution: The diagonal length can be easily determined using an equation which uses the side length of a square multiplied by the square root of 2. All we need to do is plug in the values and simplify the expression.
<u>Plug in the values</u>
<u>Simplify the expression</u>
Looking at the answer options that have been provided, the option that best fits our scenario is option A, 13.