Answer:
BD = 12 :)
Step-by-step explanation:
Alright, we'll need the Pythagorean theorem for this!
So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)
DC = 5
We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:
BD^2 + DC^2 = BC^2
BD^2 + 5^2 = 13^2
BD^2 + 25 = 169
BD^2 = 169 - 25 = 144
BD = √144 = 12 :)
Answer is B. Have a nice day.
coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
Answer:
The domain of the function is all real values of x, except
and 
Step-by-step explanation:
We are given the following function:

It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with 
Using bhaskara, the denominator is 0 for these following values of x:



The domain of the function is all real values of x, except
and 
Answer: 6 sticks
Step-by-step explanation:
Given
Joe needs
butter for each cake
One stick of butter is equivalent to 0.5 cup
So, joe need
for each cake
To bake 8 cakes, it is
