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sertanlavr [38]
2 years ago
14

Which expressions are polynomial?

Mathematics
1 answer:
Korolek [52]2 years ago
5 0
Polynomial means more than 1 term when all like terms are combined
terms are seperated by plus or minus symbols
you can't combine placeholders and numbers

y is 1 term, not poly
4x^3+y is 2 term, poly
2+s is 2 term, poly

answer is 4x^3+y and 2+s





cubic means highest power of the placeholder is 3
quadratic means highest power of placeholder is 2

trinomial means 3 terms

yep, 3 terms

4x^2+3x+5
highest power is 2
quadratic trinomial
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Given the diagram below, find the value of x.
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Step-by-step explanation:

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Ricky has 3/4 of a bag of Skittles. He wants to split the rest between between his 5 friends. What fraction of the bag will each
Wittaler [7]

Answer:

  • 3/20, with the assumptions below.

Explanation:

The question seems incomplete.

In order to show you the procedure, I make some assumptions.

Assuming that Ricky wants to split the full content of the 3/4 of a bag between his 5 friends, to find what fraction of the bag will each friend receive you must divide 3/4 by 5.

The operation is:

        \dfrac{3}{4}\div 5

Convert the whole number 5 into fraction using 1 as denominator:

       \dfrac{3}{4}\div \dfrac{5}{1}

Transform the division into multiplication changing the divisor into its reciprocal:

       \dfrac{3}{4}\times \dfrac{1}{5}

Multiply numerator with numerator and denominator with denominator:

       \dfrac{3\times 1}{4\times 5}=\dfrac{3}{20}\leftarrow answer

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Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

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