Recall the double angle identity for cosine:

It follows that

Since 0° < 22° < 90°, we know that sin(22°) must be positive, so csc(22°) is also positive. Let x = 22°; then the closest answer would be C,

but the problem is that none of these claims are true; cot(32°) ≠ 4/3, cos(44°) ≠ 5/13, and csc(22°) ≠ √13/2...
To answer this problem, we can use the power rule such that the result of the operations of the powers on the left side is equal to power on the right side. In this case, the right side's power is 200. On the left side, the tentative sum is 60 - 18 or equal to 42. Thus, the remaining exponent to be added on the left side is 158. Answer is x^158
Ok to find dy/dx of x+2y=xy we take derivative of both sides with respect to x
1+2dy/dx = x*dy/dx +y*dx/dx
1+ 2dy/dx = x*dy/dx + y* 1
2dy/dx +1 = x*dy/dx + y
2y’ + 1 = xy’ + y
2y’ + 1 - xy’ = y
2y’ -xy’ = y - 1
y’(2-x) = y - 1
so we get finally
y’= (y-1)/(2-x)
Hope this helps you understand the concept! Any questions please ask! Thank you so much!!
Answer:6
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
