(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
Step-by-step explanation:
80 over 100*150
80 divided by 100=0.8 *150=1208student
0.8 *60=48
The original square has the area (8 in)^2 = 64 in^2.
If we mult. this area by 36, we get the area of a larger square 2304 in^2.
The new side length is sqrt(2304 in^2), or 48. In other words, the original square has side length 8 in, but the 'new' square has side length 48 in.
(0.7)(0.4)=0.28 because 7×4 is 28 and you just add a 0
Answer:
-0.01
Step-by-step explanation:
