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alisha [4.7K]
3 years ago
12

A demand function often expresses the price at which x items can be sold. Typically, the lower the price is, the more items ther

e are that can be sold at that price, that is, the greater the demand there is at that price. Suppose p = $400 - $0.2x is the demand function for widgets. If we want to sell 100 widgets, where should we set the price? If we can sell 100 widgets for that price, how much total revenue would we receive from the sale of those 100 widgets? Where should we set the price if we want to sell 1200 widgets? If we can sell 1200 widgets for that price, how much total revenue would we receive from the sale of those 1200 widgets?
Mathematics
1 answer:
balu736 [363]3 years ago
5 0
I would start at 2000 because of 400/.2 is 2000 idk sorry 
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Simplify the following leaving your answer in positive index<br><br> 1) (x/y)^-4 x (y/x)^8
Basile [38]

Answer:

(\frac{x}{y})^{-4} * (\frac{y}{x})^8 = (\frac{y}{x})^{12

Step-by-step explanation:

Given

(\frac{x}{y})^{-4} * (\frac{y}{x})^8

Required

Determine the solution to this

(\frac{x}{y})^{-4} * (\frac{y}{x})^8

In law of incides:

\frac{a}{b} = \frac{b}{a}^{-1}

This implies that:

(\frac{x}{y})^{-4} * (\frac{y}{x})^8 is equivalent to:

(\frac{y}{x})^{-(-4)} * (\frac{y}{x})^8

(\frac{y}{x})^{4} * (\frac{y}{x})^8

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(\frac{y}{x})^{4+8

(\frac{y}{x})^{12

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(\frac{x}{y})^{-4} * (\frac{y}{x})^8 = (\frac{y}{x})^{12

5 0
3 years ago
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DENIUS [597]

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answer:

x=-8

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3 years ago
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