Question

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

Answer 1

Since point L is merely found on the line MN, ML and LN are considered to be line segments. So adding both line segments should add up to line MN's total length which is 31 units. We can use the given relations to create a mathematical equation as follows:

Given: MN = 31; ML = h - 15; LN = 2h - 8

MN = ML + LN

Substituting the given values:
31 = h - 15 + 2h - 8
31 = 3h - 23

It is necessary to solve for the value of h. To do this, we must isolate h and solve for it:

Adding 23 to both sides of the equation:
31 + 23 = 3h - 23 + 23
54 = 3h
h = 18

Substituting the value of h to the equation of LN we get the following:
LN = 2(18) - 8
LN = 36 - 8
LN = 28

Therefore the value of LN is 28.