Answer:
a) 
b) 
c) the points of the form (x, -x) for x≠0
Step-by-step explanation:
a)
If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be
On one hand we have,
On the other hand,
So
b)
The domain of definition of F is
i.e., all the plane X-Y except the (0,0)
c)
Here we want to find all the points such that
where k is a real number other than 0.
But this means
So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0
Answer:
y = - 4x + 16
Step-by-step explanation:
Assuming you require the equation of the line passing through the points.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 4) and (x₂, y₂ ) = (5, - 4)
m =
=
= - 4, thus
y = - 4x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 4), then
4 = - 12 + c ⇒ c = 4 + 12 = 16
y = - 4x + 16 ← equation of line
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3r+1w=5
5r+1w=80
System of equations :)