1. phenotype = black and long hair 2: brown and long hair 2
phenotype ratio = 1:1 and genotype = BbLL, BbLl,bbLL, bbLl
genotype ratio= 1:1:1:1.
2. probability of 50% progeny to be normal tailed and funny eyed is there.
3. 3/16 or 18.75% is the probability of long winged black body fly.
Explanation:
1. information given in cat:
long hair = LL, short hair ll, black hair colour BB, Brown hair colour bb
cross between:
homozygous hair length and heterozygous hair colour X heterozygous hait length and homozygous recessive hair colour
genotype = BbLL X bbLl
punnet square:
BL bL
bL BbLL bbLL
bl BbLl bbLl
phenotype = black and long hair 2: brown and long hair 2
phenotype ratio = 1:1
genotype = BbLL, BbLl,bbLL, bbLl
genotype ratio= 1:1:1:1
2. given that in fish:
Normal tail NN (dominant), fancy tail nn (recessive), funny eyes ff (recessive), normal eyes FF (Dominant)
cross between
fancy tail funny eye X Heterozygous normal tail funny eye fish)
genotype = nnff X Nnff
probability of normal tailed funny eye fish=?
cross between in puunet square:
nf nf
Nf Nnff Nnff
nf nnff nnff
phenotype = 2 normal tail funny eye: 2 fancy tail funny eye
there will be probability of 50% progeny to be normal tailed and funny eyed.
3. given that in fly:
gray body GG and long wing LL is dominant
black body gg and short wing is recessive
probability of black body long fly=?
2 heterozygous gray body and long winged bodies crossed
genotype is GgLl
Punnet square:
Gl GL gL gl
Gl GGll GGLl GgLl Ggll
GL GGLl GGLl GgLL GgLl
gL GgLl GgLL ggLL ggLl
gl Ggll GgLl ggLl ggll
3/16 is the probability of long winged black body fly.
